Common home decoration material usage calculation method
2024-10-06 13:01:02
The common specifications of solid wood flooring are 900*90*18mm, 750*90*18mm, 600*90*18mm. The rough calculation method is: room area÷ floor area*1.08=accurate calculation method using floor number: (room length÷ floor length )*(Room Width/Floor Width) = Use a floorboard with a length of 5m and a width of 3m. Use the 900*90*18mm floor as an example: The room is 5m long and the board is 0.9m wide = 6 rooms are 3m wide. Width 0.09m=34 Blocks Length 6 Blocks*Width 34 Blocks=Total Board Total 204 Blocks Solid wood floor coverings usually have 5% to 8% of lossy wood floor construction methods, including lining, direct laying and patching. Three kinds, but the calculation of the number of surface wood floor is the same, only the total area of ​​the wood floor plus 8% of the loss can be. However, when laying out the floor, it is also necessary to calculate the large wooden squares and the blockboards with paved base layer for calculation. Accounting for these woods can be found on the construction drawings to find out their specifications and structure, and then calculate the total amount. If the specifications are not specified on the construction drawing, the quantity can be calculated according to conventional methods. The conventional wooden base for racking wood floors is 60*80mm, the base blockboard is 20mm, and the large wooden squares are 600mm apart. Every 100 square meters of shop floor requires large wooden square strips of 0.94 cubic meters and blockboard of 1.98 cubic meters.
Composite floor common specifications are 900 * 90 * 18mm, 750 * 90 * 18mm, 600 * 90 * 18mm a rough calculation: room area ÷ 0.228 * 1.05 = number of floor blocks to 5m long, 3m wide room as an example: long room 5m Panel length 1.2m = 5 blocks Room width 3m Panel width 0.19m = 16 blocks 5 blocks * width 16 blocks = total plate 80 blocks Description: Composite wood floors often have 3% -5% in the pavement The loss, if calculated in terms of area, do not ignore this part of the amount. It usually uses a soft floor mat to increase the elasticity, reduce noise, and its amount is about the same as the floor area.
Coatings Latex Coatings Latex coatings are basically divided into 5 liters and 15 liters. Taking the 5 liters capacity commonly used in the family as an example, the theoretical painting area of ​​5 liters is 35 square meters twice. Rough calculation method: Floor area *2.5÷35=accurate calculation method using barrels: (length + width) *2*room height = wall area length * width = top surface area (wall area + top surface area - doors and windows Area) ÷ 35 = For example, a room with a length of 5m, a width of 3m, and a height of 2.6m is used as an example. The wall area of ​​the room and the top brush area are calculated as follows: Wall area: (5m+3m)*2*2.6m=41.6 Square meter top area: (5m*3m) = 15 square meters Coating amount: (41.6 + 15) ÷ 35 square meters = 1.4 barrels Note: The above is only the theoretical amount of brushing, because the coating should be added with appropriate amount of water during the construction process. Therefore, the above amount is only the minimum amount of brushing.
Common floor tile specifications are 600*600mm, 500*500mm, 400*400mm, 300*300mm.
The rough calculation method: Room area floor tile area *1.1 = exact calculation method for the number of bricks: (Room length ÷ brick length) * (Room width ÷ brick width) = Number of bricks with a room length 3.6m, width 3.3m , using a 300*300mm floor tile as an example:
Room 3.6m long ÷ Brick length 0.3m = 12 blocks Room width 3.3m ÷ Brick width 0.3m = 11 Blocks length 12 blocks * Wide 11 blocks = Total blocks 132 blocks Description: When accounting for ground floor tiles, take into account the cut Loss, handling loss, plus 3% loss. When laying floor tiles, the required cement and sand per square meter must be determined according to the original ground conditions. The cement mortar layer is usually laid on the ground, which requires 12.5 kg of ordinary cement and 34 kg of medium sand per square meter.
The stone consumption of the ground stone floor is approximately the same as that of the tile, except that the floor mortar layer is slightly thicker. In the calculation, taking into account the cut-off loss and handling loss, about 1.2% of the loss can be added. When laying ground stone, the required cement and sand per square meter should be determined according to the original ground conditions. Usually, 15 mm thick cement mortar is laid on the ground, which requires 15 kg of ordinary cement and 0.05 cubic meters of medium sand per square meter.
Wall tiles For complex wall surfaces and shaped wall surfaces, the area should be calculated based on the area of ​​expansion. After the total area of ​​each specification is calculated and then divided by the size of the specification, the number of sheets of various specifications (units are blocks) can be obtained. Finally, add about 1.2% of the loss.
There are many varieties of ceramic tiles. When accounting, you should first find out the position of the tiles of various types of tiles from the construction drawings, and then calculate the tile area at each position. Then add the area of ​​tiles of the same variety of specifications to the total area of ​​various tiles, and finally add about 3% of the loss. The general wall surface is plastered with various tiles using ordinary techniques. Each square meter requires 11 kg of ordinary cement, 33 kg of medium sand, and 2 kg of lime paste. On the cylinder surface, ordinary ceramics are used to inlay all kinds of tiles, requiring 13kg of ordinary cement, 27kg of medium sand, and 3kg of plaster.
When inserting tiles on the wall, 107 glue is often added to the cement. In this way, the wall surface is plastered with 12kg of ordinary cement, 13kg of medium sand, and 0.4kg of 107 glue. If this method is applied to the column surface, ordinary cement 14kg, medium sand 15kg, and 107 glue 0.4kg per square meter are required. Note: The white cement that needs to be sew-scratched after affixing is about 0.5kg/m2. The amount of cotton weaving used for scrubbing porcelain is about 1 kg per 100 square meters.
Wallpaper common wallpaper specifications are 10m long and 0.53m wide. Rough calculation method: Floor area *3 = Total area of ​​wallpaper ÷ (0.53*10) = Number of wallpaper rolls Accurate calculation method: Total wallpaper length ÷ Room actual height = Number of components used ÷ Number of components in use unit = Use wallpaper The number of rolls is fixed because of the wallpaper size, so when calculating its usage, pay attention to the actual length of the wallpaper. Usually, the actual height of the room should be used to subtract the height of the corner board and the top line. In addition, the door and window area of ​​the room should also be subtracted from the number of components used. This calculation method is suitable for plain or fine-grained wallpaper. In the collage of wallpapers, the flowers should be considered. The bigger the pattern is, the greater the loss is. Therefore, it needs to buy about 10% more than the actual amount.
Curtains Normal curtains are mostly flat curtains. Before calculating curtain material, first determine the size of the finished curtain according to the specifications of the window. The finished curtain should cover 0.15m to the right and left of the window frame and double folds. When installing curtains to 1-2cm from the ground. Calculation method: (window width +0.15*2) *2 = finished curtain width ÷ width * curtain height = curtain fabric curtain curtain calculation method: curtain width * 3 fold 1.50m width = width ( Curtain height + free edge) = number of required fabric meters if the curtain curtain, such as width 1.92m * 0.48m meters of material used 1.92m * 3 times ÷ 1.50m = 3.84, that is 4 cloth 4 * (0.48 + 0.2m) = 2.72m
The main material of the wood molding line is the wood line itself. During the calculation, the wooden lines on all surfaces are calculated according to the specifications. The so-called calculation according to the specifications, that is, the wood lines are divided into pressure angle line, pressure line and decorative line three categories, including the angle line, semicircular line, nail line, convex line, corrugated lines and other varieties, each species may be There are different sizes. The calculation is to add the same type and specification of wood lines, plus the amount of wear. Generally, for small-sized wood strips with a width of 10 to 25 mm, the loss is 5 to 8%, and the large-sized wood strips having a width of 25 to 60 mm have a loss of 3 to 5%. For some of the larger size circular arc wood, because it needs to be customized or special processing, it is generally required to list its radius size and number. The auxiliary materials for the wood lines are nails and glue. If nails are used for fixing, 0.5 boxes are required for every 100m of wooden lines, and small-sized wooden lines are usually used with 20mm nail guns. If you use ordinary nails (commonly known as 1 inch round nails), about 0.3kg per 100m. The adhesive glue of the wood line is generally white latex, 309 glue, etc. The amount of wood used for every 100m is 0.4~0.8kg.
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Composite floor common specifications are 900 * 90 * 18mm, 750 * 90 * 18mm, 600 * 90 * 18mm a rough calculation: room area ÷ 0.228 * 1.05 = number of floor blocks to 5m long, 3m wide room as an example: long room 5m Panel length 1.2m = 5 blocks Room width 3m Panel width 0.19m = 16 blocks 5 blocks * width 16 blocks = total plate 80 blocks Description: Composite wood floors often have 3% -5% in the pavement The loss, if calculated in terms of area, do not ignore this part of the amount. It usually uses a soft floor mat to increase the elasticity, reduce noise, and its amount is about the same as the floor area.
Coatings Latex Coatings Latex coatings are basically divided into 5 liters and 15 liters. Taking the 5 liters capacity commonly used in the family as an example, the theoretical painting area of ​​5 liters is 35 square meters twice. Rough calculation method: Floor area *2.5÷35=accurate calculation method using barrels: (length + width) *2*room height = wall area length * width = top surface area (wall area + top surface area - doors and windows Area) ÷ 35 = For example, a room with a length of 5m, a width of 3m, and a height of 2.6m is used as an example. The wall area of ​​the room and the top brush area are calculated as follows: Wall area: (5m+3m)*2*2.6m=41.6 Square meter top area: (5m*3m) = 15 square meters Coating amount: (41.6 + 15) ÷ 35 square meters = 1.4 barrels Note: The above is only the theoretical amount of brushing, because the coating should be added with appropriate amount of water during the construction process. Therefore, the above amount is only the minimum amount of brushing.
Common floor tile specifications are 600*600mm, 500*500mm, 400*400mm, 300*300mm.
The rough calculation method: Room area floor tile area *1.1 = exact calculation method for the number of bricks: (Room length ÷ brick length) * (Room width ÷ brick width) = Number of bricks with a room length 3.6m, width 3.3m , using a 300*300mm floor tile as an example:
Room 3.6m long ÷ Brick length 0.3m = 12 blocks Room width 3.3m ÷ Brick width 0.3m = 11 Blocks length 12 blocks * Wide 11 blocks = Total blocks 132 blocks Description: When accounting for ground floor tiles, take into account the cut Loss, handling loss, plus 3% loss. When laying floor tiles, the required cement and sand per square meter must be determined according to the original ground conditions. The cement mortar layer is usually laid on the ground, which requires 12.5 kg of ordinary cement and 34 kg of medium sand per square meter.
The stone consumption of the ground stone floor is approximately the same as that of the tile, except that the floor mortar layer is slightly thicker. In the calculation, taking into account the cut-off loss and handling loss, about 1.2% of the loss can be added. When laying ground stone, the required cement and sand per square meter should be determined according to the original ground conditions. Usually, 15 mm thick cement mortar is laid on the ground, which requires 15 kg of ordinary cement and 0.05 cubic meters of medium sand per square meter.
Wall tiles For complex wall surfaces and shaped wall surfaces, the area should be calculated based on the area of ​​expansion. After the total area of ​​each specification is calculated and then divided by the size of the specification, the number of sheets of various specifications (units are blocks) can be obtained. Finally, add about 1.2% of the loss.
There are many varieties of ceramic tiles. When accounting, you should first find out the position of the tiles of various types of tiles from the construction drawings, and then calculate the tile area at each position. Then add the area of ​​tiles of the same variety of specifications to the total area of ​​various tiles, and finally add about 3% of the loss. The general wall surface is plastered with various tiles using ordinary techniques. Each square meter requires 11 kg of ordinary cement, 33 kg of medium sand, and 2 kg of lime paste. On the cylinder surface, ordinary ceramics are used to inlay all kinds of tiles, requiring 13kg of ordinary cement, 27kg of medium sand, and 3kg of plaster.
When inserting tiles on the wall, 107 glue is often added to the cement. In this way, the wall surface is plastered with 12kg of ordinary cement, 13kg of medium sand, and 0.4kg of 107 glue. If this method is applied to the column surface, ordinary cement 14kg, medium sand 15kg, and 107 glue 0.4kg per square meter are required. Note: The white cement that needs to be sew-scratched after affixing is about 0.5kg/m2. The amount of cotton weaving used for scrubbing porcelain is about 1 kg per 100 square meters.
Wallpaper common wallpaper specifications are 10m long and 0.53m wide. Rough calculation method: Floor area *3 = Total area of ​​wallpaper ÷ (0.53*10) = Number of wallpaper rolls Accurate calculation method: Total wallpaper length ÷ Room actual height = Number of components used ÷ Number of components in use unit = Use wallpaper The number of rolls is fixed because of the wallpaper size, so when calculating its usage, pay attention to the actual length of the wallpaper. Usually, the actual height of the room should be used to subtract the height of the corner board and the top line. In addition, the door and window area of ​​the room should also be subtracted from the number of components used. This calculation method is suitable for plain or fine-grained wallpaper. In the collage of wallpapers, the flowers should be considered. The bigger the pattern is, the greater the loss is. Therefore, it needs to buy about 10% more than the actual amount.
Curtains Normal curtains are mostly flat curtains. Before calculating curtain material, first determine the size of the finished curtain according to the specifications of the window. The finished curtain should cover 0.15m to the right and left of the window frame and double folds. When installing curtains to 1-2cm from the ground. Calculation method: (window width +0.15*2) *2 = finished curtain width ÷ width * curtain height = curtain fabric curtain curtain calculation method: curtain width * 3 fold 1.50m width = width ( Curtain height + free edge) = number of required fabric meters if the curtain curtain, such as width 1.92m * 0.48m meters of material used 1.92m * 3 times ÷ 1.50m = 3.84, that is 4 cloth 4 * (0.48 + 0.2m) = 2.72m
The main material of the wood molding line is the wood line itself. During the calculation, the wooden lines on all surfaces are calculated according to the specifications. The so-called calculation according to the specifications, that is, the wood lines are divided into pressure angle line, pressure line and decorative line three categories, including the angle line, semicircular line, nail line, convex line, corrugated lines and other varieties, each species may be There are different sizes. The calculation is to add the same type and specification of wood lines, plus the amount of wear. Generally, for small-sized wood strips with a width of 10 to 25 mm, the loss is 5 to 8%, and the large-sized wood strips having a width of 25 to 60 mm have a loss of 3 to 5%. For some of the larger size circular arc wood, because it needs to be customized or special processing, it is generally required to list its radius size and number. The auxiliary materials for the wood lines are nails and glue. If nails are used for fixing, 0.5 boxes are required for every 100m of wooden lines, and small-sized wooden lines are usually used with 20mm nail guns. If you use ordinary nails (commonly known as 1 inch round nails), about 0.3kg per 100m. The adhesive glue of the wood line is generally white latex, 309 glue, etc. The amount of wood used for every 100m is 0.4~0.8kg.
Don't forget to recommend this to friends posted on QQ/MSN (Jiangsu Construction Team, Xi'an 20 years experience in construction, consulting Q1057545818)
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